2015-02-18 5:06 GMT+01:00 Udayakumar Rayala <uday.ray...@gmail.com>:
> Do you want the check if your initial code is working correctly? Because
> when I ran it, this is the output with 100 numbers:
>
> (1 3 7 9 13 15 21 25 31 33 37 43 49 51 63 67 69 73 75 79 87 93 99)
>
That is the correct output:
http://en.wikipedia.org/wiki/Lucky_number
There was a stupid mistake: it should return @current-list instead of
current-list.
> I have modified it like this. I have highlighted what I have changed.:
>
> (defn indexed-sieve [index this-list]
> (keep-indexed
> (fn [i v]
> (if (= 0 (mod (inc i) index))
> nil
> v))
> this-list))
>
> (defn lucky-numbers [max-value]
> (let [current-list *(atom (range 1 max-value)) *
>
> current-index *(atom 2)*]
>
> (while (< @current-index (count @current-list))
> (reset! current-list (indexed-sieve *@current-index*
> @current-list))
> (reset! current-index (inc @current-index)))
> @current-list))
>
> This give the following output:
>
> (1 3 7 13 19 27 39 49 63 79 91)
>
> This seems more correct.
>
> You can further convert the while to loop recur to avoid using atoms.
>
There was a solution posted with recur. Two problems:
- It gives a StackOverflowError with 1000000 and 100000. My solution has no
problem with those values. At the moment I am trying 10000000, but it will
take two hours two finish I am afraid.
- It takes about two times as long
to execute
--
Cecil Westerhof
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