The multiple-binding form of let can be recursively transformed into nested
lets:
(let [name1 value1 name2 value2 ... name value] body)
---->
(let [name1 value1] (let [name2 value2] ... (let [name value] body)))
All you're doing with your let form is shadowing the name; there's no
mutation. If you had something like this:
(let [x 1]
(let [x (inc x)]
(println x)) ;; prints 2
(println x)) ;; prints 1
it would be more obvious; it's less apparent in your case because there's
no room for the extra forms.
On Wed, Feb 11, 2015 at 5:49 PM, gvim <gvi...@gmail.com> wrote:
> On 12/02/2015 01:44, Laurens Van Houtven wrote:
>
>> Hi,
>>
>> You're confusing mutation with single assignment. You're not mutating
>> anything: 1 is still 1, 2 is still 2; you're just assigning the same name
>> to different numbers. The numbers themselves are immutable.
>>
>>
> It's x that bothers me, not the values assigned to it. I don't quite get
> it as x seems to behave here like any old mutable variable in Ruby or
> Python even if it's not called mutation. I suppose I've just never really
> "got" this (big) one :(
>
>
> gvim
>
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