The difference is how rest args are handled. From the "recur" documentation:
In particular, if the recursion point was the top of a variadic fn method, > there is no gathering of rest args - a single seq (or null) should be > passed. > So your two calls are not the same. f1 calls (recur x some-seq) which is the same as (apply f1 x some-seq). f2 calls f1 without apply, so f1's args are at that moment x and a seq of one item containing the seq used to call. To get the results you expect, change f2 to (defn f2 [x & ys] (if x (apply f2 (not x) ys) ys)) On Tuesday, January 20, 2015 at 4:17:58 AM UTC-6, Hello Funk wrote: > > This stumped a few of us on #clojure, with a debate as to whether this is > a compiler error or has a legitimate explanation. > > My initial examination: > > https://www.refheap.com/96295 > > A more minimal example: > > https://www.refheap.com/96296 > > What's going on? > > Andrew > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
