Hi all,
I've got this: `[1 3 4 5 7 9 10 11 12]`
and I'd like to turn it into this: `[[1] [3 4 5] [7] [9 10 11 12]]`.
That is, I'd like to group consecutive numbers together (the final goal
being to produce something like `["1" "3-5" "7" "9-12"]`, but that's the
easy part).
I haven't found an easy way to do this. Here's what I've come up with in
Clojure:
~~~clojure
#!/usr/bin/env lein-exec
(def v [1 3 4 5 7 9 10 11 12])
(defn congeal-consecutives
[coll]
(reduce (fn [accum x]
(if (= x (inc (last (last accum))))
(concat (butlast accum)
[(conj (last accum) x)])
(concat accum
[[x]])))
[[(first coll)]]
(rest coll)))
(prn (congeal-consecutives v))
~~~
and here's it done in Python:
~~~python
#!/usr/bin/python3
v = [1, 3, 4, 5, 7, 9, 10, 11, 12]
def congeal_consecutives(coll):
accum = [[ coll[0] ]]
more = coll[1:]
for x in more:
if x == accum[-1][-1] + 1:
accum[-1].append(x)
else:
accum.append([x])
return accum
print(congeal_consecutives(v))
~~~
Can anyone suggest a better / simpler / more easily-understandable way to
do this in Clojure?
Thanks,
-- John
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