Thanks Laurens 

 That solved it. :)

On Monday, 13 October 2014 14:04:16 UTC+5:30, Laurens Van Houtven wrote:
>
> Hi Ashish, 
>
>
> At first sight, this looks like a numerical precision problem. 1e80 is a 
> floating point type, not an integer type. You may want to try with e.g. 
> 1000000000000000N (note the N; that makes it a bigint). I don’t know of any 
> nice syntax for describing extremely large bigints; e.g exponent notation. 
>
>
> hth 
> lvh 
>
>
>
> On 13 Oct 2014, at 10:20, Ashish Negi <thisismy...@gmail.com <javascript:>> 
> wrote: 
>
> > 
> > 
> > Hi I am programming in clojure and though the problem of modulo inverse 
> has nothing to do with language i am stuck at this code - 
> > 
> > (defn EulerDiv [x p] 
> > 
> >   
> > (let [ToMod (+ p 2)] 
> > 
> >     
> > (loop [num 1 toPow (int p) numDouble x] 
> > 
> >       
> > (if (= 0 toPow) 
> >   
> >         num 
> >         
> > (let [numDouble2 (rem (* numDouble numDouble) ToMod) 
> > 
> >               halfToPow 
> > (int (/ toPow 2))] 
> > 
> >           
> > (if (odd? toPow) 
> > 
> >             
> > (recur (rem (* num numDouble) ToMod) 
> > 
> >                    halfToPow 
> >                    numDouble2 
> > ) 
> > 
> >             
> > (recur num halfToPow numDouble2)) 
> > 
> > 
> >           
> > )))) 
> > 
> >   
> > ) 
> > It seems to give me right answers for small Primes but when i am using 
> it in a problem with Bigger primes i am getting answers other than result 
> like : 
> > 
> > (= 2 (mod (* 4 (EulerDiv 2 (- 3 2))) 3)) 
> > This prints true 
> > 
> > (def ToMod (+ 10e8 7)) 
> > ( = 1 (int (mod (* 2 (EulerDiv 2 (- ToMod 2))) ToMod)) ) 
> > This prints false. 
> > 
> > Also there is rem and mod in clojure. mod makes the output positive and 
> hence i can not use it in between the calculations. 
> > 
> > The problem is that of programming calculator grammar for evaluating 
> evpressions like  "4/-2/(2 + 8)" 
> > 
> > Thanks 
> > 
> > 
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