I'd use another channel on which I put vectors of the correct length, with
an intermediate loop that takes from the first channel, accumulates until
the vector has the right size, and then put the vector on the second
channel.

There might be a better solution with transducers, though. (Or without.)

On Wednesday, 3 September 2014, cig <clifford.goldb...@gmail.com> wrote:

> Thanks Timothy, that makes sense.
>
> A follow on question if you don't mind.
>
> I would like to 'take' n items off of a channel, but wait until n items
> are available rather than eagerly returning the way take does. Do you have
> any ideas on how
> I could achieve this?
>
> On Tuesday, 2 September 2014 22:23:10 UTC+2, tbc++ wrote:
>>
>> It's because into is pulling items as fast as it can from take. Sure the
>> buffer might get full but then into takes another value allowing take to
>> continue.
>>
>> Timothy
>>
>>
>> On Tue, Sep 2, 2014 at 1:48 PM, cig <clifford...@gmail.com> wrote:
>>
>>> Hi
>>>
>>> I was expecting the following example to park, waiting for the 'out'
>>> channel to be cleared. Could anybody explain why 'take' does not
>>> park when the output buffer size is smaller than the number of entries
>>> being taken from the input channel?
>>>
>>> (def from (to-chan [1 2 3 4 5 6 7]))
>>> (<!! (into [] (take 4 from *2*)))       ;; note: the output channel
>>> buffer size is 2 (less than 4 items being taken off of the 'from' channel)
>>>
>>> ;; => [1 2 3 4]
>>>
>>>
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>>
>>
>> --
>> “One of the main causes of the fall of the Roman Empire was that–lacking
>> zero–they had no way to indicate successful termination of their C
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>> (Robert Firth)
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