The JVM optimises sections of code that are frequently executed, so the
second expression benefits from the optimisation that happens during the
first expression. My guess is that if you were to swap the two expressions
around, you'd find that the first expression always takes longer, no matter
which way around it is.

Benchmarking libraries like Criterium get around this by "warming up" the
JVM with a few practice runs before recording the benchmarks. I'd advise
using Criterium over clojure.core/time if you want to benchmark things
accurately.

- James


On 12 July 2014 10:29, Cecil Westerhof <cldwester...@gmail.com> wrote:

> I do the following (with range-length 1e8):
>     (time (let [[t d] (split-with #(< % 12) (range range-length))]
>                [(count d) (count t)]))
>
>     (time (let [[t d] (split-with #(< % 12) (range range-length))]
>                (into [] (reverse [(count t) (count d)]))))
>
> ​This gives:
>     "Elapsed time: 68105.338314 msecs"
>     [99999988 12]
>     "Elapsed time: 11545.667394 msecs"
>     [99999988 12]
>
> So the first expression​
> ​ takes as six times as long to evaluate. ​
> ​I understood that this has to do with that in the first case there is
> head retention. But I do not understand this. What is happening here?​
>
>
> --
> Cecil Westerhof
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