Is there a better way to take this...
[[:a [1 2]]
[:b [3 4]]]
and convert it to this...
[[:a 1]
[:a 2]
[:b 3]
[:b 4]]
than using a loop like this...
(defn doit [id v]
(loop [a (first v) r (rest v) result []]
(if a
(recur (first r) (rest r) (conj result [id a]))
result)))
???
Thanks!
,boz
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