The call to (index) returns this vector

([0 \:] [1 \a] [2 \space] [3 \4] [4 \space] [5 \:] [6 \b] [7 \space] [8 \1]
[9 \space] [10 \:] [11 \c] [12 \space] [13 \3] [14 \space] [15 \:] [16 \d]
[17 \space] [18 \4])

And, 3 here is in the 13th position. Your (cond) in index function is
picking up the :else branch.


On Tue, May 13, 2014 at 6:44 PM, gamma235 <jesus.diama...@gmail.com> wrote:

> I am reading The Joy of Clojure now and am finishing chapter 5 on sequence
> abstractions. There is an example given that demonstrates how to locate the
> index of an element in a sequence by value, but I don't understand why the
> character lookup here is returning 13. Can somebody please explain this to
> me?
>
> (defn index [coll]
>>   (cond
>>    (map? coll) (seq coll)
>>    (set? coll) (map vector coll coll)
>>    :else (map vector (iterate inc 0) coll)))
>>
>> (defn pos [pred coll]
>>   (for [[i v] (index coll) :when (pred v)] i))
>>
>
>
>> (pos \3 ":a 4 :b 1 :c 3 :d 4")
>
>
>
> => 13
>
>
> J
>
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