Did this get returned from my htc
Sent from my HTC
----- Reply message -----
From: "Angus" <anguscom...@gmail.com>
To: <clojure@googlegroups.com>
Subject: How to convert this simple (and inefficient) fibonacci function to #
format
Date: Wed, Nov 13, 2013 17:41
I know this fibonacci function is not optimal but I want to learn one step
at a time. I want to be able to apply this approach to 4clojure which
disallows a lot of things including defn.
This is my implementation so far:
(defn fib [x]
(cond
(= x 0) 0
(= x 1) 1
:else
(+ (fib (- x 1)) (fib (- x 2)))))
So I thought about something like this:
(#(fn fib [x]
(cond
(= x 0) 0
(= x 1) 1
:else
(+ (fib (- x 1)) (fib (- x 2)))))
8)
But trying that in a REPL I get error:
clojure.lang.ArityException: Wrong number of args (1) passed to:
sandbox28956$eval28971$fn
So how can I call this as a one line REPL?
I though using apply with a one element list might work, but no.
(apply #(fn fib [x](cond (= x 0) 0 (= x 1) 1 :else (+ (fib (- x 1)) (fib
(- x 2))))) '(8))
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