Yep, sure.  Thanks.
On 13 Aug 2013 05:56, "Michael-Keith Bernard (SegFaultAX)" <
mkbernard....@gmail.com> wrote:

> For the partition-by solution to work, you have to ensure that the result
> set from the query is sorted by the foreign key:
>
> (partition-by identity "aaabbbcccaaabbbcc")
> ;;=> ((\a \a \a) (\b \b \b) (\c \c \c) (\a \a \a) (\b \b \b) (\c \c))
> (partition-by identity (sort "aaabbbcccaaabbbcc"))
> ;;=> ((\a \a \a \a \a \a) (\b \b \b \b \b \b) (\c \c \c \c \c))
>
>
> On Monday, August 12, 2013 11:17:29 AM UTC-7, Colin Yates wrote:
>>
>> Great - thanks!
>>
>>
>> On 12 August 2013 19:07, Jonah Benton <jo...@jonah.com> wrote:
>>
>>>
>>> Sounds like a job for partition-by:
>>>
>>> http://clojuredocs.org/**clojure_core/clojure.core/**partition-by<http://clojuredocs.org/clojure_core/clojure.core/partition-by>
>>>
>>>
>>>
>>> On Mon, Aug 12, 2013 at 1:55 PM, Colin Yates <colin...@gmail.com> wrote:
>>>
>>>> Is there such a thing as a lazy group-by for a sequence of elements
>>>> when the elements are sorted on the criteria used to group them?  I can
>>>> imagine how one would look in a few lines of Clojure code but I am
>>>> surprised there isn't one already.
>>>>
>>>> My actual criteria is that I am pulling things from a database that
>>>> live on the "many" side of a one-many and I want to sort on the "one" FK.
>>>>
>>>> This is all based on the assumption that http://clojuredocs.org/**
>>>> clojure_core/clojure.core/**group-by<http://clojuredocs.org/clojure_core/clojure.core/group-by>
>>>>  is
>>>> eager!
>>>>
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