drclj <deepikaro...@gmail.com> writes:
> Thanks everyone, in the apply function source code I see
>
> ([^clojure.lang.IFn f args]
> (. f (applyTo (seq args))))
>
> Seems the (applyTo (seq args)) returns arg parameters,
>
> And the f is invoked only once:
>
> (. f args)
I think you’re missing that `.` is a special form with special
evaluation rules. The following forms are all equivalent:
(. f (applyTo (seq args))
(. f applyTo (seq args))
(.applyTo f (seq args))
With the last being syntactic sugar converted during macro-expansion to
the middle form.
So there’s no `applyTo` *function*, just the `applyTo` *method* of IFn
instance `f`.
OOC, do you have a background using R or similar languages? I was
confused myself learning R, because what R calls `apply` is nothing like
what Lisps call `apply` and (as others in this thread pointed out) is
more similar to what Clojure calls `map`.
-Marshall
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