It's definitely got to do with the code, the right way to test it out
will be to wrap the form in a function and then calling it twice. Like
so -
(time
(let [x (fn [] (Thread/sleep 2000)
(+ 1 1))]
[(x) (x)]))
;=> "Elapsed time: 4002.0 msecs"
;=> [2 2]
Hope that helps.
Regards,
BG
On Tue, Jul 23, 2013 at 8:34 PM, Ryan Moore <niclas1...@gmail.com> wrote:
> There is an example in the book The Joy of Clojure on p.262 that uses
> futures that I evaluated in the REPL.
>
> user> (time
> (let [x (future (do (Thread/sleep 2000)
> (+ 1 1)))]
> [@x @x]))
> "Elapsed time: 2000.809 msecs"
> [2 2]
>
> I figured that taking out the future would cause the execution to take twice
> as long, however, when I try this:
>
> user> (time
> (let [x (do (Thread/sleep 2000)
> (+ 1 1))]
> [x x]))
> "Elapsed time: 2000.512 msecs"
> [2 2]
>
> as you see it takes about the same amount of time. Does this have something
> to do with the REPL evaluating things or maybe the newer version of Clojure
> handles things differently from the Joy of Clojure book?
>
> Thanks
>
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Baishampayan Ghose
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