you can use group-by as you showed and then reduce-kv over them map
replacing each key with '(count key)'...I don't see a way of doing this
in one-pass using group-by alone...
Jim
On 08/07/13 20:25, Colin Yates wrote:
Hi,
I have a sequence of items and want to group them into categories, the
value of which is a function of the item. This sounds exactly what
group-by is after.
The kicker is that the function could return multiple values. Imagine
each item was a date range and I wanted to group them by the number of
days in that date range.
For example, (group-by #(range 1 (inc %)) [1 2 3] => {(1) [1] (1 2)
[2] (1 2 3) [3]}. I want {1 [1] 2 [1 2] 3 [1 2 3]}.
Any ideas?
Thanks!
Col
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