Realizing a lazy-seq is done through a synchronized method see: https://github.com/clojure/clojure/blob/master/src/jvm/clojure/lang/LazySeq.java#L37
No race conditions. Cedric Greevey writes: > What, precisely, happens if two threads sharing a reference to a single > lazy sequence try to realize the same element at the same time? If the > sequence is completely pure and deterministic, so any attempt to realize a > particular element will produce a single particular value consistently > (unlike, say, (repeatedly rand) or a file-seq where relevant parts of the > filesystem are being concurrently modified), is the worst-case scenario > that the two threads will redundantly perform the same calculation, with no > effect other than a minor hit to performance and, in particular, no effect > on the program semantics? > > -- -- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
