Since Clojure is not a pure language, you cannot even expect (a == a) ==>
((f a) == (f a)), so I do not think it is a stretch to break that theorem
for b != a.

Most importantly, Clojure's notion of equality is centered around the
notion of simple data, irrespective of the specific type of object you have
built to encapsulate it.


On 9 April 2013 11:00, Tassilo Horn <t...@gnu.org> wrote:

> JvJ <kfjwhee...@gmail.com> writes:
>
> > This is just an idle curiosity up for discussion, but in Clojure, if
> > (= a b) is true, then given some function f, it is not necessarily
> > true that (= (f a) (f b))
>
> I think this axiom isn't true in any language.  Take `str` / toString()
> as an example.  If that statement was true, then equal objects would
> need to have equal string representations.  Then you either couldn't
> have 1 and 1.0 be equal, or you would need to print all numbers as
> floats.  An even better counter example are sets versus sorted sets.
>
> Bye,
> Tassilo
>
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