My Question would be: why are you trying to do this? You mentioned you are
working with a database, I assume that means SQL (as almost all NoSQL
Databases support some kind of JSON which doesnt require your
"workarround"). Most SQL Database support array types natively, while
support might be a little itchy (at least in JDBC terms) it still beats a
comma seperated list.
In all other cases just use clojure.core/pr-str and the new
clojure.edn/read-string when reading it back.
Just my 2 cents,
/thomas
On Thursday, October 28, 2010 2:18:08 AM UTC+2, andrei wrote:
>
> Hi all,
>
> I work with a database and need a function, that will convert Clojure
> sequence to a string with a comma-separated elements. E.g.,
>
> (comma-separated (list 1 2 3 4 5)) ==> "1, 2, 3, 4, 5"
>
> It must work with any data type - ints, strings, other lists, etc.
> E.g. for a list of strings it must generate
>
> (comma-separated (list "1" "2" "3" "4" "5")) ==> "\"1\", \"2\",
> \"3\", \"4\", \"5\""
>
> I tried `cl-format` function from clojure.contrib.pprint package:
>
> (cl-format nil "~{~S~^, ~}" lst)
>
> It works fine, but is too slow. Next, I tried such function:
>
> (defn comma-separated [s]
> (if (= (type (first s)) String)
> (chop (chop (chop (str "\" (apply str (interleave s
> (repeatedly (fn [] "\", \"")))))))
> (chop (chop (apply str (interleave s (repeatedly (fn [] ",
> ")))))))))
>
> This one works much faster (~20 times), but it is ugly and still
> doesn't cover all cases.
>
> So, what is the fastest way to generate such list?
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