That makes sense. Thanks. On Friday, 29 March 2013 22:21:21 UTC-4, Alan Malloy wrote: > > Comparator.compare returns an int. (int 0.2) and (int -0.2) both > return 0. Thus, your comparator is returning 0, saying "I don't care > what order these go in". > > On Mar 29, 6:44 pm, JvJ <kfjwhee...@gmail.com> wrote: > > Alright check this out: > > > > ;; Normal subtraction as comparator sorts in ascending order > > (sort-by identity #(- %1 %2) [1 -1]) > > (-1 1) > > > > ;; Reverse subtraction as comparator sorts in descending order > > (sort-by identity #(- %2 %1) [1 -1]) > > (1 -1) > > > > ;;======================================= > > ;; And now with values of -0.1, 0.1 > > > > ;; Reverse subtraction as comparator sorts in descending order > > (sort-by identity #(- %2 %1) [0.1 -0.1]) > > (0.1 -0.1) > > > > ;; Normal subtraction STILL sorts in descending order?? > > (sort-by identity #(- %1 %2) [0.1 -0.1]) > > (0.1 -0.1) >
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