My point here isn't to tickle your brain but point out that there's a bit
of misunderstanding about how core.logic works and what facilities you
should use to handle your problem.

It should be clear soon enough that it will be very difficult to formulate
your problem in terms of facts or conde.

You said you wanted q to be a member of a some list A. Then why not use
membero? But you don't want q to be a member of some list B. Then try to
write a not-membero in terms of disequality.

(run* [q]
 (membero q '(1 2 3 4))
 (not-membero q '(3 4 5 6)))

David


On Thu, Mar 28, 2013 at 4:12 PM, JvJ <kfjwhee...@gmail.com> wrote:

> Any other hints?  I'd love to spend time on this brain tickler, but I have
> other things to do.
>
>
> On Thursday, 28 March 2013 16:05:00 UTC-4, JvJ wrote:
>>
>> Alright, I'm starting to get it.... but not quite there
>>
>> (run* [q]
>>     (fresh [x]
>>   (conde
>>    ( (== q 1) )
>>    ( (== q 2) )
>>    ( (== q 3) )
>>    ( (== q 4) ))
>>
>>   (conde
>>    ( (== x 3) )
>>    ( (== x 4) )
>>    ( (== x 5) )
>>    ( (== x 6) ))
>>
>>   (!= q x)))
>> (1 1 1 2 1 2 2 2 3 4 3 3 4 4)
>>
>> On Thursday, 28 March 2013 15:44:01 UTC-4, David Nolen wrote:
>>>
>>> This won't work. Rewrite this example w/o using facts and try to
>>> understand why it won't work.
>>>
>>> David
>>>
>>> On Thu, Mar 28, 2013 at 3:37 PM, JvJ <kfjwh...@gmail.com> wrote:
>>>
>>>> Here's what I'm trying...
>>>>
>>>> (facts a  [[1]
>>>>      [2]
>>>>      [3]
>>>>      [4]])
>>>> nil
>>>> (facts b  [[3]
>>>>      [4]
>>>>      [5]
>>>>      [6]])
>>>>
>>>> (run* [q]
>>>>     (a q)
>>>>     (fresh [x]
>>>>    (b x)
>>>>    (!= q x)))
>>>> (1 1 2 1 1 2 2 2 3 4 3 3 4 4)
>>>>
>>>> So what the heck is this all about?
>>>>
>>>> On Thursday, 28 March 2013 15:17:24 UTC-4, David Nolen wrote:
>>>>
>>>>> negation is hard. This has come up several times. It may be possible
>>>>> to a better form of negation as failure via delays, but this not high on 
>>>>> my
>>>>> current priority list. Patches to make it work are of course most welcome.
>>>>>
>>>>>
>>>>> On Thu, Mar 28, 2013 at 2:54 PM, JvJ <kfjwh...@gmail.com> wrote:
>>>>>
>>>>>> Thanks, but there's another aspect to this.
>>>>>>
>>>>>> Let's say I had two relations A and B, and I wanted all q such that
>>>>>> (A q)
>>>>>> (not (B q))
>>>>>>
>>>>>> How would that work?
>>>>>>
>>>>>>
>>>>>> On Thursday, 28 March 2013 14:50:33 UTC-4, Jim foo.bar wrote:
>>>>>>
>>>>>>> clojure.set/difference
>>>>>>> 'membero' combined with its negated form?
>>>>>>>
>>>>>>> Jim
>>>>>>>
>>>>>>> On 28/03/13 18:47, JvJ wrote:
>>>>>>> > In core.logic, how do the following: "Give me everything that is a
>>>>>>> > member of list A and not a member of list B"?
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