(defprotocol symbolicExpr
(evalx [this args]))
(deftype x [a])
(let [y #(+ 1 2)]
(extend-type x
symbolicExpr (evalx [this args] (y))))
(evalx (x. 0) 0)
On Wednesday, December 26, 2012 6:16:13 PM UTC-8, Sunil Nandihalli wrote:
>
> Hi Everybody,
> It looks like the following way of definition is not allowed.. what is a
> good alternative way of doing this
>
> (defprotocol symbolicExpr
>
>
> (evalx [this args]))
>
> (let [y #(+ 1 2)]
>
>
> (deftype x [a]
>
>
> symbolicExpr
>
>
> (evalx [this args]
>
>
> (y))))
>
> I know I can do a (def y #(+ 1 2)) but that would unnecessarily make the
> variable global to the namespace. and I don't want to put it inside the
> method either, since it would have to re-evaluate the same var multiple
> times when I know it will remain constant across *evalx* method calls.
> what is a good way of achieving my goal without making *y *global to the
> namespace?
> Thanks,
> Sunil.
>
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