On Mon, Jul 30, 2012 at 11:05 PM, Vinay D.E <devi...@gmail.com> wrote: > I tried putting a print and it works as expected.
Because you are realizing the whole of i to print it. > 1) I assumed that printing out [i @a] instead of [@a i] should realize 'i' No, [i @a] creates a two-element vector of a lazy-seq and a value (the deref of a). Then, when the REPL prints that vector, it realizes the lazy-seq. > 2) If I put a breakpoint in the predicate for take-while, it gets hit ( I Yes, it is hit while i is being realized. > 3) This is the strangest observation of all: In the debugger I can see that > 'a' is getting incremented, its changing when the breakpoint is hit! but > the baffling thing is, when the result is printed out, I still get 0 as the > value for a. Because the value of @a is bound before i is realized, so 0 is bound into the vector, and then i is realized during which process you see a being incremented. > Isn't (print i) the same as [i @a] ? since i is realized first, shouldn't > @a be correctly printed? No, see above. > Why is the breakpoint showing me that a is changing ? Because it _is_ changing but _after_ the top level of the vector has been evaluated. -- Sean A Corfield -- (904) 302-SEAN An Architect's View -- http://corfield.org/ World Singles, LLC. -- http://worldsingles.com/ "Perfection is the enemy of the good." -- Gustave Flaubert, French realist novelist (1821-1880) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
