I discovered partition-all and came up with this function:
(fn [l x] (concat (butlast l) (partition-all 2 (concat (last l)
[x]))))
user> ((fn [l x] (concat (butlast l) (partition-all 2 (concat (last l)
[x]))))
'()
10)
((10))
user> ((fn [l x] (concat (butlast l) (partition-all 2 (concat (last l)
[x]))))
'(( 1 2 ) ( 20 30) (40))
50)
((1 2) (20 30) (40 50))
user> ((fn [l x] (concat (butlast l) (partition-all 2 (concat (last l)
[x]))))
'(( 1 2 ) ( 20 30) (40 50))
60)
((1 2) (20 30) (40 50) (60))
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