"Jim - FooBar();" <jimpil1...@gmail.com> writes:

> (doto foo
>  (.bar x)
>  (.baz y)
>  (dotimes [i 10] (.zab g)))
>
> won't work because foo is substituted as the second argument of
> 'dotimes'!

The docs clearly state that.

> It has to be 'do' instead of 'doto'...

Then, you need (.bar foo x), (.baz foo y), and (.zap foo g), too.

Bye,
Tassilo

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