reading material: http://blog.fogus.me/2009/09/04/understanding-the-clojure-macro/
When you say (-> 3 (partial f 2)) that evaluates to (partial 3 f 2) - which is obviously not what you want. Likewise, (-> 3 fp) expands to (fp 3), which works fine, as you noticed. The important thing to remember is that the threading operator is a macro. On Mon, Apr 16, 2012 at 12:53 PM, larry <larrye2...@gmail.com> wrote: > I trying to grok partial and -> so I have the following example. > > (defn f[x y] (+ x y)) > > ((partial f 2) 3) works as expected , returning 5 > > but if I try to use -> > > (-> 3 (partial f 2)) > > I get #<core$partial$fn__3796 clojure.core$partial$fn__3796@4c629f43> > > But if I first define > > (def fp (partial f 2)) > > then > > (-> 3 fp) returns 5 as expected > > What's going on ? > > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with your > first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
