I am trying to learn how to use core.logic. Here is a toy problem that I am thinking about.
(run* [q] (fresh [a b c] (membero a [1 2 3]) (membero c [1 2 3]) (== b 2) (!= a b) (!= a c) (!= b c) (== q [a b c]))) I would like to create a function that replaces the three != lines, something like, (distincto [a b c]) such that I could rewrite the above problem as (run* [q] (fresh [a b c] (membero a [1 2 3]) (membero c [1 2 3]) (== b 2) (distincto [a b c]) (== q [a b c]))) I tried to write several functions but they are all end up inside some variant of a col, [(!= a b)(!= a c)(!= b c)]. Thus, I either need someone to help me figure out how do write the distincto function, or what to call on [(!= a b)(!= a c)(!= b c)] to get it to work. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en