I'm stupid today... I meant:
(contains? #{(int 1)} (long 1))
false
On Aug 2, 10:19 am, Oskar Kvist <oskar.kv...@gmail.com> wrote:
> Btw, that should be fixed in 1.3 I think.
>
> On Aug 2, 10:18 am, Oskar Kvist <oskar.kv...@gmail.com> wrote:
>
>
>
>
>
>
>
> > Sorry, didn't read your post properly. Maybe it's because the ints are
> > of different types.
>
> > (contains? [(int 1)] (long 1))
> > false
>
> > On Aug 2, 10:13 am, Oskar Kvist <oskar.kv...@gmail.com> wrote:
>
> > > "Returns true if _key_ is present in the given collection, otherwise
> > > returns false."
>
> > > For sets like #{200, 210} the values also count as keys.
>
> > > On Aug 2, 10:10 am, Petr Gladkikh <petrg...@gmail.com> wrote:
>
> > > > I spent hour already and can not understand what is wrong here.
>
> > > > I want to filter collection based on a nested field of collection
> > > > element having some value:
>
> > > > (println pinned-ids)
> > > > ; #{200, 210}
>
> > > > (println (contains? pinned-ids 200))
> > > > ; true
>
> > > > (println (map #(.. % :field :id) new-states))
> > > > ; (10 20 21 100 200 500 400 210) ; This collection contains both 200
> > > > and 210
>
> > > > However no test is true
> > > > (println (map #(contains? pinned-ids (.. % :field :id)) new-states))
> > > > ; (false false false false false false false false)
>
> > > > Why "contains?" return false for all elements despite that set
> > > > pinned-ids contains some of elements?
>
> > > > --
> > > > Petr Gladkikh
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