Ah, thanks. I think the pulling-apart of last and butlast was a
remnant of my trying to do this with foldl instead of foldr :P.
On Mar 10, 10:38 am, Takahiro <fat...@googlemail.com> wrote:
> more concise:
>
> (defn enmap [args]
> (reduce #(hash-map %2 %1) (reverse args)))
>
> 2011/3/11 Takahiro <fat...@googlemail.com>:
>
>
>
>
>
>
>
> > Interesting. Here is my attempt.
>
> > (defn enmap [args]
> > (let [[fs & res] (reverse args)]
> > (reduce (fn [v k] (hash-map k v)) fs res)))
>
> >> (enmap [1 2 3 4 {5 6 7 8}])
> > => {1 {2 {3 {4 {5 6, 7 8}}}}}
>
> >>(let [[tail more] ((juxt last (comp reverse butlast)) [1 2 3 4 {5 6 7 8}])]
> >> (reduce #(hash-map %2 %1) tail more))
> > I still cannot understand what is going on in this code. juxt always
> > make my head crashed.
>
> > Thanks.
>
> > 2011/3/11 Damien Lepage <damienlep...@gmail.com>:
> >> Hi
>
> >> I wrote a function to transform a variable number of arguments into
> >> embedded
> >> maps.
> >> Here is what it does:
> >>> (enmap 1 2)
> >> {1 2}
> >>> (enmap 1 2 3)
> >> {1 {2 3}}
> >>> (enmap 1 2 3 4)
> >> {1 {2 {3 4}}}
> >>> (enmap 1 2 3 4 {5 6 7 8})
> >> {1 {2 {3 {4 {5 6, 7 8}}}}}
> >> Here is my implementation:
> >> (defn enmap [arg & args]
> >> (if-let [more (butlast args)]
> >> (let [k (last more), v (last args)]
> >> (if-let [even-more (butlast more)]
> >> (apply enmap arg (concat even-more (list (hash-map k v))))
> >> (enmap arg (hash-map k v))))
> >> (apply hash-map arg args)))
> >> Two things bother me:
>
> >> Is there a way to make this function less complicated? without recursion
> >> maybe?
> >> Is there something simpler than (concat even-more (list (hash-map k v)) to
> >> append an element at the end of a sequence?
>
> >> Thanks
> >> --
> >> Damien
>
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