I'm using a macro that, stripped down to just expose my problem, looks
like this:

(defmacro quoted-param
  [x]
  `(println '~x))

It's all nice if I call it like

(quoted-param 23)

It will print the number 23. The following, however, will print
"asdf", rather than 23:

(def asdf 23)
(quoted-param asdf)

Which is of course what the quote is supposed to do. But is there any
way to get that macro to expand to using the value of asdf, rather
than the symbol itself? Or can only changing the macro fix this? I
fear the latter, which would imply that using quotes like that in a
macro should be done with great care, I guess. Adding a quote when
'calling' the macro is easy...

Cheers
Eugen

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