Does this make the processing a little clearer?
#"(?<=([ ab]))?([ab])\2*"
Have all good days,
David Sletten
On Aug 21, 2010, at 10:02 PM, CuppoJava wrote:
> Wow that's so short! Thanks Chouser! I will abstain from showing the
> awful hack that I've been working with currently.
> -Patrick
>
> On Aug 21, 8:45 pm, Chouser <chou...@gmail.com> wrote:
>> On Sat, Aug 21, 2010 at 7:11 PM, CuppoJava <patrickli_2...@hotmail.com>
>> wrote:
>>> Hi Everyone,
>>
>>> I'm extremely stuck on this simple regex question, which I'm sure
>>> someone with a little more experience will be able to write in a
>>> second. I would really appreciate the help.
>>
>>> Given a string consisting of a's, b's, and spaces: "aaa bbb abb ab
>>> bb"
>>
>>> I want to tokenize this into string's of a's and b's.
>>> eg. "aaa", "bbb", "a", "bb", "a", "b", "bb"
>>
>>> AND also, I have to be able to tell which of the strings of b's was
>>> preceded with an "a", and which was preceded by a space.
>>
>> (->> "aaa bbb abb ab bb"
>> (re-seq #"(?<=(.))?(\w)\2*")
>> (map (fn [[s pre]] {:s s, :pre pre})))
>>
>> returns a lazy seq:
>> ({:s "aaa", :pre nil}
>> {:s "bbb", :pre " "}
>> {:s "a", :pre " "}
>> {:s "bb", :pre "a"}
>> {:s "a", :pre " "}
>> {:s "b", :pre "a"}
>> {:s "bb", :pre " "})
>>
>> --Chouserhttp://joyofclojure.com/
>
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