1. In case coll is a LazySeq why does (seq coll) realize its first element? I thought seq just did a type conversion and all of list, vector .. etc implemented Seqable or something.
Because seq is defined as returning nil for an empty sequence. The only way to find that out for a lazy sequence is to realize the first element.
2. Why is there no other way to determine an empty coll except (not (seq coll)).
user=> (empty? []) true -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
