On 2010 Mar 23, at 4:13 PM, Meikel Brandmeyer wrote:
(let [[s1 & s1tail] seq1
In the above destructuring the first element of s1tail is also
realised.
That is what I mean with "one step ahead". I'm not sure why it is done
like this. I does not seem necessary. But I'm not an expert in the
destructuring code…
would (let [s1 (first seq1)
s1tail (rest seq1)] ...)
be any better? rest says it calls seq on its argument, and that would
force as well?
Hmmm... So only things like map are able to realize first without
realizing (first (rest seq1)) too?
-D
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