Mike, I'd say this is not your fault. I'm a clojure newbie too and the answer
to your question is nowhere to be found in Clojure's barren documentation.
You're using the right command line stuff, but you need to change your code:
;; foo.clj
(ns foo (:load "foo-util"))
(defn main []
(print "hello from main\n")
(frob))
(main)
;; foo-util.clj
(in-ns 'foo)
(defn frob []
(print "hello from frob\n"))
- Greg
On Feb 5, 2010, at 4:38 PM, Mike Jarmy wrote:
> That yields ".;lib/clojure.jar", just as we'd expect. I also tried,
> "java -cp foo.clj;foo-util.clj;lib/clojure.jar clojure.main foo.clj",
> but that gave the same error. All of these classpaths work when I
> comment out the calls to "(require 'foo-util)" and "(frob)" -- which
> you would expect, since at that point foo.clj is just a trivial hello
> world script.
>
> So we are agreed that my clojure code *ought* to work, given the
> correct class path, but it does not? So this must be some clojure
> classloader thing? Maybe I'm doing something out of the ordinary
> here, and there's a more closure-idiomatic way to do it? It does seem
> like the right approach to me that every file in a given directory
> should have the same namespace.
>
> On Fri, Feb 5, 2010 at 4:16 PM, Meikel Brandmeyer <m...@kotka.de> wrote:
>> Hi,
>>
>> Am 05.02.2010 um 22:13 schrieb Sean Devlin:
>>
>>> This expression will provide a string that is the classpath
>>>
>>> ((into {} (System/getProperties)) "java.class.path")
>>>
>>> There's probably a more elegant way... anyone?
>>
>> Simply (System/getProperty "java.class.path")?
>>
>> Sincerely
>> Meikel
>>
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