I think it's easier to think about combining predicates separately
from your file-filtering code. I'd use a higher-order function like
the following
(defn combine-preds
[& preds]
(fn [& args] (every? #(apply % args) preds)))
then filter files like
(filter (combine-preds pred1 pred2) (file-seq in-dir))
Perry
On Jan 21, 2:08 pm, nwalex <neillalexan...@gmail.com> wrote:
> Brilliant. Thanks Dan, that did the trick.
>
> On Jan 21, 8:01 pm, Dan Schmidt <dan.schm...@gmail.com> wrote:
>
>
>
> > I don't know how efficient it is (or how idiomatic it really is), but
> > this should work:
>
> > (defn find-files
> > "Find files in directory that match predicates pred & others"
> > [in-dir pred & others]
> > (reduce (fn [xs f] (filter f xs)) (file-seq in-dir) (cons pred others)))
>
> > Dan
>
> > On Thu, Jan 21, 2010 at 2:47 PM, nwalex <neillalexan...@gmail.com> wrote:
> > > I'm very new to Clojure, and to functional programming in general. Can
> > > anyone tell me the idiomatic way to implement this function?
>
> > > (defn find-files
> > > "Find files in directory that match predicates pred & others"
> > > [in-dir pred & others]
> > > (filter pred (file-seq in-dir)))
>
> > > What is the best way to filter a sequence using multiple predicates? I
> > > want to return a sequence containing the files that match predicate
> > > pred and all other predicates bound to 'others'.
>
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