On 28 Gru, 20:57, Robert Campbell <rrc...@gmail.com> wrote:
> How might I add a third and final condition, where those candidates
> with equal scores AND equal counts are all returned together?
Reduce can work with functions like
f : x * y -> x
So we can modify function closest to be like that (untested):
(closest [ v1s v2]
(if (empty v1s)
v2
(cond
(and (= (matching (first v1s)) (matching v2))
(= (count (first v1s)) (count v2))) (into
v1s v2))
(or (> (matching (first v1s)) (matching v2))
(and (= (matching (first v1s)) (matching v2))
(< (count (first v1s)) (count v2))))
[v1]
:else [v2])))
Also, we use matching on the same arguments a lot, so it would be good
to memoize that function.
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