On Wed, Oct 28, 2009 at 4:20 AM, Timothy Pratley
<timothyprat...@gmail.com>wrote:

> On Oct 28, 6:04 pm, John Harrop <jharrop...@gmail.com> wrote:
> > It always starts with the zeroth item and skips ahead however many
> elements
> > were specified. The second argument is the n in
> > "every nth item". (You can think of it as the index of the SECOND item to
> > take, so (take-nth 3 foo) takes index 0 of foo, then index 3, and so on.)
>
> Yes I agree it makes perfect sense, but I don't think the doc string
> really says that.


They probably thought it didn't need to, because the function name does say
that. :)

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