ah, that works too! thanks!
On Wed, Jun 3, 2009 at 3:48 AM, Laurent PETIT <laurent.pe...@gmail.com> wrote:
>
> If what you really want to do is treat those sequences as sets, then
> you can use clojure.seq/difference:
>
> 1:1 user=> (def seq1 (list 2 3 4 5 6 7 8 9 10))
> #'user/seq1
> 1:2 user=> (def seq2 (list 4 6 8 10))
> #'user/seq2
> 1:3 user=> (require 'clojure.set)
> nil
> 1:4 user=> (clojure.set/difference (set seq1) (set seq2))
> #{2 3 5 7 9}
> 1:5 user=> (seq (clojure.set/difference (set seq1) (set seq2)))
> (2 3 5 7 9)
> 1:7 user=>
>
>
> 2009/6/3 Wilson MacGyver <wmacgy...@gmail.com>:
>>
>> More newbie questions. :)
>>
>> If I have two sequences as follow:
>>
>> (2 3 4 5 6 7 8 9 10)
>> (4 6 8 10)
>>
>> what's the best way to subtract the 2nd sequence from the first one?
>>
>> The best I can come up with was to do (first) on 2nd sequence and turn
>> around
>> and do a (remove) on the first sequence, etc until I exhaust the 2nd
>> sequence.
>>
>> is there a better way?
>>
>> Thanks,
>>
>> --
>> Omnem crede diem tibi diluxisse supremum.
>>
>> >
>>
>
> >
>
--
Omnem crede diem tibi diluxisse supremum.
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