Hi, Am 18.04.2009 um 14:32 schrieb Michael Hunger:
that also happens with #((+ % 1))
#(%) is equivalent to (fn [x] (x)). So giving an integer as argument will basically to call an integer => *BOOM*. As you correctly noted. #((+ % 1)) will be transformed to (fn [x] ((+ x 1))) and again you will be trying to call an integer, because (+ x 1) is integer if x is one. Your problem are actually the double parens! #(+ % 1) is equivalent to (fn [x] (+ x 1)) and will work as you expect. Sincerely Meikel
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