I always need all of them. Figuring out how many that are combinatorially
is surprisingly tricky!

On Thu, Oct 31, 2019 at 11:33 AM Satyam Ramawat <satyamrama...@gmail.com>
wrote:

> I mean you can limit the answer according to need, by running into loop
> until end users value satisfy, will can be either 5,20 or N. so it will
> throw output according to run of a loop.
>
> On Thu, 31 Oct 2019 at 4:28 PM, Laurens Van Houtven <_...@lvh.io> wrote:
>
>> Satyam: you're suggesting limiting the answers asked from run, or
>> something else?
>>
>> On Thu, Oct 31, 2019 at 11:24 AM Satyam Ramawat <satyamrama...@gmail.com>
>> wrote:
>>
>>> On a very simple way, you can restrict by using if statement by crossing
>>> checking the count/length of the list,
>>> https://clojuredocs.org/clojure.core/if
>>>
>>> On Tuesday, October 29, 2019 at 11:06:54 PM UTC, Laurens Van Houtven
>>> wrote:
>>>>
>>>> Hi,
>>>>
>>>> I'm trying to divide a list into 3 lists such that (= my-list (concat a
>>>> b c)). I guess you could say I'm writing concato :-)
>>>>
>>>> (l/run n
>>>>   [a b c]
>>>>   (l/fresh [A B] ;; uppercase are internal accumulators
>>>>     (l/appendo a b A)
>>>>     (l/appendo A c B)
>>>>     (l/== B '(p q r s))))
>>>>
>>>> ... running this program with small n (let's say 5) works fine. Ask for
>>>> more answers than there are (e.g. 20) and it ostensibly runs forever.
>>>>
>>>> 1. Why?
>>>> 2. How do I fix that? (I've tried reordering the goals.)
>>>>
>>>> thanks
>>>> lvh
>>>>
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