Here's another. (defn remove-at [v & idxs] (vec (for [i (range (count v)) :when (not ((set idxs) i))] (v i))))
- Jeff On Wednesday 18 February 2009 12:07, Chouser wrote: > > On Wed, Feb 18, 2009 at 12:30 PM, Telman Yusupov <use...@yusupov.com> wrote: > > No prettier, but a bit faster: > > (defn remove-at42 [coll & indexes] > (let [iset (set indexes)] > (loop [i (int 0) sq (seq coll) v []] > (if-not sq > v > (recur (inc i) > (next sq) > (if (iset i) > v > (conj v (first sq)))))))) > > --Chouser --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
