Thanks a lot, everyone. Isn't (reduce conj [] (apply map vector [[:a :b] [1 2] ['a 'b]])) equivalent to (into [] (apply map vector [[:a :b] [1 2] ['a 'b]])) though?
On Feb 16, 3:55 pm, Laurent PETIT <laurent.pe...@gmail.com> wrote: > And to get the enclosing vector: > > (reduce conj [] (apply map vector [[:a :b] [1 2] ['a 'b]])) > > 2009/2/16 David Nolen <dnolen.li...@gmail.com> > > > > > I'm sure it can be done, but it's not clear to me if you have a vector of > >> vectors > >> how Stuart's solution would work: > > >> 1:15 user=> (map vector vecs) > > > ([[:a0 :a1 :a2]] [[:b0 :b1 :b2]]) > > > (apply (partial map vector) [[1 2 3] ['a 'b 'c] ["cat" "dog" "bird"]]) > > > works on a vector of vectors. The OP wanted a vector of vectors as a result > > where the subvector length is the same as the number of vectors originally > > passed in. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
