The selections function in combinatorics returns more than what I
need. (selections [ 1 2 3 4 5] 3) will return both (1 2 3) and (3 2
1), etc. However, I still need (1 1 1) (2 2 2), etc. I've tried
several times to write a function to filter out the 'duplicates', but
haven't quite got it.
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