On Jan 15, 2:05 pm, Daniel Jomphe <danieljom...@gmail.com> wrote:
> > (every? identity [true false true])
>
> So obvious, yet so overlooked each time I read the function names in
> the api!
Hi Daniel,
FYI, the reason "and" doesn't work is that it's a macro, not a
function. Only functions can be used with "apply".
If you had a hypothetical "and function" like this:
(defn and-fn [& args] (every? identity args))
Then you could use apply:
(apply and-fn [true true])
;=> true
(apply and-fn [true false true])
;=> false
But, obviously, just using "every?" in the first place is a lot
simpler.
-Stuart Sierra
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