Yet another question, this time just a curiosity. Sorry for the plethora of posts, but I'm trying to make sure I understand lazy seqs properly.
Why doesn't (count (doall (range 10000000000))) cause an out-of memory error? doall says it causes the entire seq to reside in memory at one time, yet: user> (count (range 100000000)) ; uses no memory, as expected 100000000 user> (count (doall (range 100000000))) ; still uses no memory!? 100000000 user> (count (doall (range 500000000))) ; even bigger, still no heap growth 500000000 user> (count (doall (map identity (range 100000000)))) ; now as expected ; Out of memory Thanks, Jason --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
