I'll take a crack at this. It may appear that the doall and dorun return something different with subsequent calls but they don't actually. The doall always returns the sequence (1 2) and dorun always returns nil.
The first time (doall x) is called the for loop executes and prints 1 2 (a side effect and is not returned from the for loop) and then returns the seq. The second time it's called x is already assigned the seq and just returns it. It does not execute the for loop again. The dorun call is similar, but instead of returning the seq of the for loop, it always returns nil. According to the api docs, dorun is used to force side effects. On Mon, Dec 15, 2008 at 9:19 PM, wubbie <sunj...@gmail.com> wrote: > > Hello, > > doall and dorun returns different results from seond run on... > e.g. > user=> (def x (for [i (range 1 3)] (do (println i) i))) > #'user/x > user=> (doall x) > 1 > 2 > (1 2) > user=> (doall x) > (1 2) > user=> (doall x) > (1 2) > user=> > > user=> (def x (for [i (range 1 3)] (do (println i) i))) > #'user/x > user=> (dorun x) > 1 > 2 > nil > user=> (dorun x) > nil > user=> (dorun x) > nil > user=> > > > What's the explanation for that? > > thanks > sun > > > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
