I agree with Stuart, I can't imagine this is how anyone new to Clojure would expect this to work:
user=> (contains? [2 3 4] 1) (contains? [2 3 4] 1) true user=> (contains? [2 3 4] 4) (contains? [2 3 4] 4) false user=> (contains? (seq [2 3 4]) 1) (contains? (seq [2 3 4]) 1) false user=> (contains? (seq [2 3 4]) 4) (contains? (seq [2 3 4]) 4) false The fact that contains? is semantically different than java.util.Collection#contains is confusing. If contains? was called contains-key?, that would be more intuitive and map to how it works in Java. On Sep 30, 5:29 pm, Stuart Halloway <[EMAIL PROTECTED]> wrote: > For your specific case you should probably be using contains?, which > works for both. > > But I agree it seems odd. > > > > > The following looks weird to me: > > > Clojure > > user=> (.contains [1 2 3] 2) > > true > > user=> (true? (.contains [1 2 3] 2)) > > false > > > AFAICS true? is implemented using identical? which tests by reference > > equality. Now since Java boolean values are boxed into Booleans we > > have > > not only Boolean.TRUE. Maybe true? (and false?) should be > > implemented in > > terms of equals? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
