Perfect! Thanks

On Aug 25, 9:22 pm, Rich Hickey <[EMAIL PROTECTED]> wrote:
> On Aug 25, 9:16 pm, John <[EMAIL PROTECTED]> wrote:
>
> > For each element, get element and next element (incrementing index by
> > one, not two), operate on the two, returning a new collection.
> > There's the brute force method, but I'm wondering if map or for or any
> > of their ilk can pull pairs at a time out of a collection, moving
> > across the collection one element at a time.
>
> partition can return a lazy sequence of sets of elements, walking by
> an arbitrary step:
>
> (partition 2 1 (range 10))
> -> ((0 1) (1 2) (2 3) (3 4) (4 5) (5 6) (6 7) (7 8) (8 9))
>
> Rich
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