On Fri, 8 Apr 2022 12:06:06 GMT, Tejesh R <[email protected]> wrote:
> Yes, the original issue was observed and raised in Windows alone...... In Mac
> and Linux the control wont even enters this logic -
>
> ```
> if (endOfLineProperty != null && !endOfLine.equals("\n")) {
> // There is an end of line string that isn't \n, have to iterate
> // through and find all \n's and translate to end of line string.
> ```
Since you mentioned in mac/linux it wont even enter the above path, then I
guess in below code
if (array[counter - 1] == '\r') {
out.write(array, last, counter - last - 1);
} else {
out.write(array, last, counter - last);
}
the else part is a no-op as in windows \r\n is present so I think always the
check `if (array[counter - 1] == '\r')` will be satisfied
If this is true, then I guess we can remove `if (array[counter - 1] == '\r')`
check too as it is always true in windows..
-------------
PR: https://git.openjdk.java.net/jdk/pull/8122
