Hello friends,
I have a question to ask.
If you define the following cases:
Case 1:
-----------
x = 1
def f():
print(x)
Case 2:
-----------
x = 1
def f():
print(x)
x = 5
print(x)
If you call the function f, in case 1 there won't be a problem, It will
print 1. But in case 2, it will give an error "UnboundLocalError: local
variable 'x' referenced before assignment"...One would think that in case
2, it should have printed 1 and 5. Any one could explain what is happening
here? Why does the interpreter get confused in the 2nd Case?
Thanks.
Regards,
Ranjith
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