On 5/1/2017 2:16 PM, Hal Finkel via cfe-commits wrote:

On 05/01/2017 12:49 PM, Daniel Berlin wrote:
On 04/21/2017 06:03 AM, Hal Finkel via Phabricator wrote:
...


   Our struct-path TBAA does the following:

      struct X { int a, b; };
      X x { 50, 100 };
      X *o = (X*) (((int*) &x) + 1);

      int a_is_b = o->a; // This is UB (or so we say)?


This is UB.
A good resource for this stuff is http://www.cl.cam.ac.uk/~pes20/cerberus/ <http://www.cl.cam.ac.uk/%7Epes20/cerberus/> which has a long document where they exlpore all of these and what various compilers do, along with what the standard seems to say.

http://www.cl.cam.ac.uk/~pes20/cerberus/notes30-full.pdf is 172 pages, and so I may have missed it, but I don't see this case. Also, I'd really like to see where the standard says this is UB. I don't see it.


The last sentence of 8:


6.5.6 Additive operators


7 For the purposes of these operators, a pointer to an object that is not an element of an array behaves the same as a pointer to the first element of an array of length one with the type of the object as its element type.

8 When an expression that has integer type is added to or subtracted from a pointer, the result has the type of the pointer operand. If the pointer operand points to an element of an array object, and the array is large enough, the result points to an element offset from the original element such that the difference of the subscripts of the resulting and original array elements equals the integer expression. In other words, if the expression P points to the i-th element of an array object, the expressions (P)+N (equivalently, N+(P)) and (P)-N (where N has the value n) point to, respectively, the i+n-th and i−n-th elements of the array object, provided they exist. Moreover, if the expression P points to the last element of an array object, the expression (P)+1 points one past the last element of the array object, and if the expression Q points one past the last element of an array object, the expression (Q)-1 points to the last element of the array object. If both the pointer operand and the result point to elements of the same array object, or one past the last element of the array object, the evaluation shall not produce an overflow; otherwise, the behavior is undefined. If the result points one past the last element of the array object, it shall not be used as the operand of a unary * operator that is evaluated.

-Krzysztof

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