================
@@ -908,6 +908,69 @@ void CodeGenFunction::EmitIfStmt(const IfStmt &S) {
incrementProfileCounter(&S);
}
+bool CodeGenFunction::checkIfLoopMustProgress(const Expr
*ControllingExpression,
+ bool HasEmptyBody) {
+ if (CGM.getCodeGenOpts().getFiniteLoops() ==
+ CodeGenOptions::FiniteLoopsKind::Never)
+ return false;
+
+ // Now apply rules for plain C (see 6.8.5.6 in C11).
+ // Loops with constant conditions do not have to make progress in any C
+ // version.
+ // As an extension, we consisider loops whose constant expression
+ // can be constant-folded.
+ Expr::EvalResult Result;
+ bool CondIsConstInt =
----------------
efriedma-quic wrote:
One case to consider:
```
int main() {
while (!__builtin_is_constant_evaluated()) {}
}
```
If you treat the condition of the loop as manifestly constant-evaluated, the
loop is finite: the condition evaluates to false. If we say it's not
manifestly constant-evaluated, but do some sort of constant-evaluation anyway,
it's a well-defined infinite loop. If we somehow treat it as manifestly
constant-evaluated for the constant evaluation, but not at runtime, it's UB.
https://github.com/llvm/llvm-project/pull/90066
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